2007-12-23 06:37:05 · 8 answers · asked by babyblue2pie 4 in Science & Mathematics ➔ Mathematics
a = 0, b = -13
a = 1, b = -10
a = 2, b = -7
In general
(a,3*a-13) = (a,b)
2007-12-23 06:42:36 · answer #1 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0⤊ 0⤋
Choose any values you want:
Let a = 5
3(5) - b = 13
15 - b = 13
b = 15 - 13
b = 2
Let a = 3
3(3) - b = 13
9 - b = 13
b = 9 - 13
b = -4
Let a = 15
3(15) - b = 13
45 - b = 13
b = 45 - 13
b = 32
Therefore 3 possible pairs for a and b are (5, 2), (3, -4), and (15, 32)
2007-12-23 14:41:58 · answer #2 · answered by Jacob A 5 · 0⤊ 0⤋
Isolate one variable. For example, solve for b.
-b = 13 - 3a
b = 3a - 13
Let a = 0, 1 and 2
a = 0, b = -13
a = 1, b = -10
a = 2, b = -7
2007-12-23 14:44:24 · answer #3 · answered by ajordan971 5 · 0⤊ 0⤋
a=0 b=-13
a=1 b=-10
a=5 b=2
2007-12-23 14:42:05 · answer #4 · answered by Michael C 2 · 0⤊ 0⤋
Since you have two variables and one equation, you don't have one unique answer. Thus for each value of b you select (which is more convenient, since it's coefficient is 1) you get a different value of x. Just try it 3 times.
2007-12-23 14:47:16 · answer #5 · answered by cattbarf 7 · 0⤊ 0⤋
6/5
5/2
7/8
2007-12-23 14:41:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
There r lots of choices..you can have (a,b)=(9,14),(8,11),(7,8)....it will go like tht
2007-12-23 14:47:09 · answer #7 · answered by scorpiotigerqueen 2 · 0⤊ 0⤋
No.
2007-12-23 14:44:00 · answer #8 · answered by Seaner 2 · 0⤊ 1⤋