Mole Question?

Question

What is the amount of mole, particle, or L for these?
30.6g H20 (water)
88g C
62g NaOH
95 mol of CO2
402g CO2..

I have sloved everyone and I believe my answers are wrong...

Answer 1

1. find the molecular weight of each compound

2.

30.6g*(1mole/18.008g) = 1.699 moles of water

88g*(1mole/12.01g) = 7.33 moles of carbon

62g*(1mole/40.01g) = 1.55 moles of sodium hydroxide

95g*(1mole/44.01g) = 2.16 moles of carbon dioxide

402g*(1mole/44.01g) = 9.13 moles of carbon dioxide

Answer 2

**1 mol = 18 g H2O (Molar Mass)**
30.6 g = 1.7 mol H2O
**1 mol = 6.02x10^23 molecules**
30.6 g = 1.02x10^24 molecules H2O
**1 mol = 22.4 L of gas at STP**
30.6g = 38.1 L of H2O

A similar process is needed for the rest of the problems, but I'm going to give only answers to save time. Use the conversion factors between ** above to help you get these values.

**1 mol = 12 g C**
88g C = 7.3mol C = 4.4x10^24 molecules C = 160 L C at STP

**1mol NaOH = 40g NaOH**
62g NaOH = 1.6 mol NaOH = 9.3x10^23 molecules NaOH = 35L NaOH at STP

95 mol CO2 = 5.7x10^25 molecules CO2 = 2100 L CO2

**1 mol = 44g CO2**

402g CO2 = 9.14 mol CO2 = 5.50x10^24 molecules CO2 = 205 L CO2 at STP