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Question

this is a physics question that not alot of people know answer it to get a 5 point best answer thank u ..........

for a constant force suppouse the duration of impact on an object doubles
a. how much impulse is increased?
B. how much is the resulting change in momentum increased?

Answer 1

Sorri, first two answerers are wrong!

Impulse = F delta t, and F is constant, delta t is doubled, so the quantity called 'impulse' is just doubled!

B. Impulse IS the change in momentum, so obviously, momentum doubles!

We can check:

Impuse = mass * delta V, where V is velocity

If impulse is doubled, mass stays same, delta V is doubled, doubling the momentum.

Answer 2

a. The impulse decreases by one-half. Impulse is change in momentum over time. If you doubling the amount of time it takes for the collision to occur, the impulse is half what it would normally be.

b. The resulting change in momentum does not change. Both objects are going to hit and come to a stop.

Here's an example of what this looks like in the real world:

The front end of most cars are made out of material that is made to collapse in on itself. You can even see the ridge that the engineers put into the hood in order to aid this process. The reason why they made that is to increase the time of the collision if the car is ever in a wreck. Increased collision time decreases the impulse, which could lead to injury of the people inside the car(s).

However, the car does eventually come to a stop no matter how much longer the collision takes. So, the loss of momentum is the same, just takes longer for that loss to occur.

Answer 3

The two are synonymous. The force is the rate of change of momentum, and is hre constant. The impulse is defined as the integral with respect to time of the force, and this is equal to the total change in momentum.

In both cases double the time and the answer doubles.

Answer 4

If the duration of the application of F is doubled, and m is constant, a will be four times greater. Thus, the impulse and change in momentum will be 4X.

Answer 5

Impulse = Avg. force X Time interval,
so for a const. force, if time is doubled, the Impulse also doubles.

Now avg. Force = Change in momentum/time
so change in momentum = Impulse = 2 times, keeping force const. if time doubles

Answer 6

The energy is multiplied by 2^2 = 4, so the
momentum doubles. Don't know what you call impulse
(I am not a native speaker).