A) +69
B)+46
C) 3±7
D) -3+7
2007-12-23 04:28:15 · 9 answers · asked by delightfulldee71 1 in Science & Mathematics ➔ Mathematics
x^2+10=59
x^2=49
x=+or- 7
2007-12-23 04:31:58 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
I think the answer is not in the choice
X^2 + 10 = 59
=> x^2 = 59 - 10
= 49
=> x = sqrt(49) = +7 or -7
2007-12-23 12:33:36 · answer #2 · answered by scorpiotigerqueen 2 · 0⤊ 0⤋
x^2 + 10 = 59
x^2 = 59 - 10
x^2 = 49
x = sqrt(49)
x = +7 or x = -7
2007-12-23 12:34:04 · answer #3 · answered by Smart Ambitious 2 · 0⤊ 0⤋
None of the above...
x^2 + 10 = 59
x^2 = 49
x = 7
2007-12-23 12:43:29 · answer #4 · answered by Chau D 2 · 0⤊ 0⤋
x^2 + 10 = 59
x^2 = 59 - 10 (switching sides)
x^2 = 49
x = square root(49)
x = +/- 7 (since both give a positive square)
2007-12-23 12:40:14 · answer #5 · answered by Blaze 3 · 0⤊ 0⤋
x^2=59-10
x^2=49
x=+(or)-7
NONE OF THE ABOVE
2007-12-23 12:37:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Solve. x^2 + 10 = 59?
substract 10 from both sides to get
x^2 = 49
answer is
x = +/- 7
2007-12-23 12:32:12 · answer #7 · answered by Any day 6 · 1⤊ 0⤋
+-7
2007-12-26 01:50:12 · answer #8 · answered by Santiago 3 · 0⤊ 0⤋
answer is +-7..
x^2=59-10
x^2=49
x=+-7
i.e. none of the option..
2007-12-23 12:32:27 · answer #9 · answered by ranjith kumar shetty 2 · 0⤊ 0⤋