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I don't know where to start
Solve (x+2)^2=12
2007-12-23 03:59:45 · 8 answers · asked by cuvelx 3 in Science & Mathematics ➔ Mathematics
(x+2)^2=12
x+2=(12)^1/2
x+2=(4*3)^1/2
x+2=2(3)^1/2
x=2(3)^1/2-2
x=2(1.7302)-2
x=3.4641-2=1.4641 approx.
Factoring the 12 important. You need a calculator to find value for sqrt(3). Luck
2007-12-23 14:19:03 · answer #1 · answered by ? 3 · 0⤊ 1⤋
(x+2)^2=12
x+2= +/- 12^1/2 (^1/2 = sqaure root)
x= -2 +/- 12^1/2
That's as far as you can simplify it unless your teacher let's you use a calculator to find square roots:
x= -2 +/- 3.464
x= 1.464 x= -5.464
Merry Christmas! =)
2007-12-23 12:22:35 · answer #2 · answered by Emily 5 · 1⤊ 0⤋
(x+2)^2=12
=> x^2+4x+4= 12
=> x^2+4x-8=0
use quadratic formula
2007-12-23 12:06:20 · answer #3 · answered by harry m 6 · 1⤊ 1⤋
I don't see why we cannot take the square root of both sides!
X + 2 = 3.464101615 therefore Check:
X = 3.464101615 - 2 then (3.46)^2 = 11.97160
11.97 = 12 approx.
X = 1.464101615
2007-12-23 12:59:09 · answer #4 · answered by gzlakewood@sbcglobal.net 4 · 1⤊ 1⤋
(x+2)^2 = 12
(x+2)^2 = [2sqrt(3)]^2
x+2 = +/- 2sqrt(3)
x = -2 + 2sqrt(3) or - 2 - 2sqrt(3)
x = 2(-1 + sqrt(3)) or - 2(1 + sqrt(3))
2007-12-23 12:06:09 · answer #5 · answered by mohanrao d 7 · 1⤊ 0⤋
(x + 2) = ± 2 â3
x = - 2 ± 2 â3
x = (- 2) ( 1 ± â3 )
2007-12-23 12:57:44 · answer #6 · answered by Como 7 · 2⤊ 0⤋
(x+2)^2=12
(x+2)=12^(1/2) or x+2=sqrt{12}
x=sqrt{12} -2
x=1.4641
2007-12-23 12:05:43 · answer #7 · answered by ♥*´`*•.katie.•*´`*♥ 2 · 1⤊ 1⤋
x+2 = sqrt12
=2sqrt3 or -2sqrt3
x= 2(1 + sqrt3) or 2(1-sqrt3)
Simple isn't it?
2007-12-23 12:04:09 · answer #8 · answered by BOND 3 · 1⤊ 1⤋