what is the square root of (8x^3)/5?

0 ⤊

what is the square root of (8x^3)/5?

2007-12-23 03:39:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

2xsqrt2x/sqrt5

rationalize denominator . Mult by sqrt5/sqrt5
get

2xsqrt 10x/5

2007-12-23 04:01:39 · answer #1 · answered by mom 7 · 0⤊ 0⤋

sqrt(8x^3)/5 = sqrt[(2x)^2*2x]/5 = 2xsqrt(2x)/5

2007-12-23 04:02:39 · answer #2 · answered by mohanrao d 7 · 0⤊ 1⤋

2xsqrt(2x) / sqrt(5)
= 0.4xsqrt(10x)

2007-12-23 04:05:14 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋

if you meant sqrt[(8x^3)/5] then

sqrt[(8x^3)/5]=sqrt[(8*x^3)/5]
=sqrt[(1.6*x^3)]
=1.264911*sqrt(x^3)

If you meant [sqrt(8x^3)]/5 then

[sqrt(8x*3)]/5=[2.8284271*sqrt(x^3)]/5=0.5656854*sqrt(x^3)

2007-12-23 04:26:56 · answer #4 · answered by scorpiotigerqueen 2 · 0⤊ 0⤋