For cosmetic reasons, we've left the burned out bulb in the socket which raised the before mentioned question. We've loosened the bulb so there's no contact but we were just wondering about the possibility of "juice" still being drawn into the point of contact.
2007-12-22 03:39:09 · 8 answers · asked by Vince T 1 in Science & Mathematics ➔ Engineering
No. When an incandescent bulb burns out or is removed from the socket no current can flow. If voltage or current equals zero no power is dissipated. P=EI If either E, voltage, or I, current, is equal to 0 the resultant power is 0 watts. Now if the bulb were a flourescent bulb then you might have a starting transformer, and then even if you remove the bulbs the transformer will continue to use about the same amount of power.
2007-12-22 03:50:37 · answer #1 · answered by CB 7 · 0⤊ 0⤋
No for the case described - bulb burnt out and loosened in socket. There is no path for current flow thus no power consumed.
Yes for any light that includes a transformer - florescent, low voltage lights, leds, etc. Current will flow in the transformer primary winding causing some small power consumption. The power will be much less than normal use since the voltage and current are out of phase. Only the resistance of the primary winding will cause loss, typically a small percentage of the normal power consumption.
2007-12-22 04:16:10 · answer #2 · answered by Growl 6 · 2⤊ 1⤋
No, if there's no circuit, (through the broken filament,
screwed in or not), there's no 'draw`.
I'm surprised you didn't worry, (Like Thurbers Maiden
Aunts), that if the bulb was unscrewed electricity might
leak out and run over the floor.
2007-12-22 06:15:21 · answer #3 · answered by Irv S 7 · 0⤊ 0⤋
No. That is the definition of burned out. The filament has broken through vibration or evaporation. There is no path for the electricity to flow through so none can be "drawn in."
2007-12-22 03:46:58 · answer #4 · answered by Rich Z 7 · 2⤊ 0⤋
No, the circuit is broken, there can be no electron flow. No power to the filament.
2007-12-22 04:02:16 · answer #5 · answered by Norrie 7 · 1⤊ 0⤋
Definitely No. There's no load (filament) at all.
2007-12-22 04:43:31 · answer #6 · answered by Gem 2 · 0⤊ 0⤋
nope if its unhooked unscrewed or burnt out then there is nothing to complete the circut leaving no electricity use
2007-12-22 03:46:36 · answer #7 · answered by d s 3 · 0⤊ 0⤋
No, it is not using any electricity because there is no current flow.
2007-12-22 03:45:36 · answer #8 · answered by Anonymous · 2⤊ 0⤋