A man (or a woman!) wants to buy an engagement ring. S/he has a choice of 4 metals (gold, silver, platinum, titanium), 3 stones (diamond, emerald, ruby) and 3 cuts of stone (Tiffany, square and round).
Assuming they must choose one specific type of metal, one type of stone and one cut, how many different ring combinations do they have to choose from?
2007-12-21 19:23:31 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4 possible choices for the metal
3 possible choices for the stone
3 possible choices for the cut
Total: 4 x 3 x 3 = 36 different rings
2007-12-21 19:27:59 · answer #1 · answered by mathman 3 · 0⤊ 0⤋
4 x 3 x 3
= 12 x 3
= 36 ring combinations
4(a choice of 4 metals)
3(a choice of 3 stones)
3(a choice of 3 cuts of stone)
2007-12-22 04:24:27 · answer #2 · answered by An ESL Learner 7 · 0⤊ 0⤋
4 types of metals x 3 types of stones x 3 types of cuts = 36 possible ring combinations..
2007-12-22 03:32:27 · answer #3 · answered by ..Kaylaboo.. 2 · 0⤊ 0⤋
36
2007-12-22 03:51:48 · answer #4 · answered by snehalu 3 · 0⤊ 0⤋
4* 3* 3 = 36
2007-12-22 04:34:56 · answer #5 · answered by ces 3 · 0⤊ 0⤋
C(4, 1)*C(3, 1)*C(3, 1) = 4*3*3 = 36 different rings.
2007-12-22 04:30:40 · answer #6 · answered by sv 7 · 0⤊ 0⤋
times choices by choices.
4x3x3=36 combinations
2007-12-24 20:23:10 · answer #7 · answered by whereskoolaidman 2 · 0⤊ 0⤋
4 metals*3stones*3cuts = 36 combinations
2007-12-22 03:59:09 · answer #8 · answered by cutie 2 · 0⤊ 0⤋
4x3x3=36
2007-12-22 03:27:15 · answer #9 · answered by Chewyconor 5 · 0⤊ 0⤋
36
since we have
4 choices of metals * 3 choices of stones * 3 cuts...
2007-12-22 03:26:50 · answer #10 · answered by --jrom-- 3 · 0⤊ 0⤋