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when u dissovle solid AgCl in water

the Ag and Cl ions seperate

say the solution is at equilibrium

if u just add more Ag ions then the dissolving of AgCl should be suppressed (thus lowering the solubility of AgCl) due to the common-ion effect so that the concentration of Ag ions can be reduced right?

but then wont suppressing the dissolving of AgCl also lower the Cl ion concentration ? since each Ag ion would be bonded to a Cl ion in the solid form?

if im right, then how do u really get back to equilibrium state?

if im wrong, correct me and explain please?

2007-12-21 18:07:28 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

You are correct. Adding Ag+ ions will suppress ionization (dissolving) of AgCl(s). Thus [Cl-] will decrease also. The whole system will reach a new equilibrium. With more [Ag+] and less [Cl-]. Ksp = [Ag+][Cl-] is still the same number, but the [Ag+] will be the amount of Ag+ that you added.

2007-12-21 18:36:19 · answer #1 · answered by steve_geo1 7 · 0 0

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