what is the value of?

Question

2+2-2*2/2(2)

Answer 1

Apply BODMAS.#
If in your question, (2) is not in the denominator, then
=2+2-2*1(2)
=2+2-2*2
=2+2-4
= 4-4
=0
THEN ANSWER IS 0 (ZERO).

If, it is in the denominator,
=2+2-2*1/2
=2+2-1
=4-1
=3
THEN ANSWER IS 3 (THREE).


#
B Brackets
O Of
D Division
M Multiplication
A Addition
S Subtraction
To apply BODMAS Move from top to bottom ie. open the brackets first .......and subtract in the end .

Answer 2

2 + 2 - 2 x 2 / 2(2)
= 4 - 4 / 2(2)
= 0 / 2(2)
= 0

Answer 3

It's BEDMAS, not BODMAS...

Brackets
Exponents
Division
Multiplication
Addition
Subtraction

2 + 2 - 2*2 / 2(2)

Do the brackets first:

= 2 + 2 - 2*2 / 4

Technically you would do the division next, but multiplication and division can go in either order.

= 2 + 2 - 2*0.5

Now the multiplication

= 2 + 2 - 1

Then the addition and subtraction

= 4 - 1

= 3

However, if the (2) is not in the denominator:

2 + 2 - 2*2/2 (2)

There is nothing to be solved in the brackets, so do the division first:

= 2 + 2 - 2*1 (2)

Then multiply:

= 2 + 2 - 2(2)
= 2 + 2 - 4

The add and subtract

= 0

Answer 4

the answer is 0