how to do a algerba problem like 4x-4=16?

Answer 1

4x = 16 + 4
4x = 20
x = 5

Answer 2

1] you write the original equation.
2] you add four to each side of the equation
3] you solve what you have left.
4] you divide each side by 4.
5] you solve what you have left and that gives you 'x'

1] 4x - 4 = 16
2] 4x - 4 + 4 = 16 + 4
3] 4x = 20
4] 4x/4 = 20/4
5] x = 5

Answer 3

x=5

Answer 4

What you do to one side of the equation, you must do to the other.
First, add 4 to both sides:
4x-4=16 changes to 4x=20
Now divide both sides by 4:
4x=20 changes to the answer, x=5.

Answer 5

Well, if I remember right, you should add 4 on both sides of the equation, so you would end up with 4x = 20.
Then, you DIVIDE each number by 4--also on both sides of the equation, so you would end up with x = 20/4, which you would then divide 20 by 4 mathematically, and end up with 5.
So x = 5.

Answer 6

get the x's on a separate side as the rest of the problem
(in this case, subtract negative four from each side, or just add four)

--> 4x=20
Then divide any number left in front of x to solve for that variable (so divide 20 by 4)

--> x=5

Answer 7

4x - 4 = 16
4x = 20
x = 5

Answer: x = 5

Proof:
4(5) - 4 = 16
20 - 4 = 16

Answer 8

Do the same operation on both sides until you get x = number

4x - 4 = 16

4x = 20 {add 4}

x = 5 {divide by 5}

Answer 9

What you need to do is isolate x in one side while the constants in the other side. so here's a step by step solution
1. add four to both sides so your equation will be
4x-4+4=16+4
The four will cancel out in the left side leaving you with
4x=20
2. Divide by the constant of x which is four to isolate x
4x/4=20/4
Thus, x=5

Answer 10

4x-4=16
4x-4+4=16+4
4x=20
x=5