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A neutron, proton and electron are all in similar but separate orbits around an uncharged black hole. Assume no interaction with any other matter and the neutron does not decay, which would fall first into the black hole and why?

2007-12-21 09:45:59 · 10 answers · asked by Frst Grade Rocks! Ω 7 in Science & Mathematics Physics

As I said, they are all in orbit, so the question really is which orbit, if any, would decay first and why?

2007-12-21 11:35:09 · update #1

Alexander is not only knowledgeable, but he can read too realizing that an orbit means, well, an orbit. When a charged particle is accelerated it will emit electromagnetic radiation as a result of the acceleration or decleration. See Bremsstrahlung radiation http://en.wikipedia.org/wiki/Bremsstrahlung , Cyclotron radiation http://en.wikipedia.org/wiki/Synchrotron_light and X-rays. In an orbit around a black hole, a charge particle is in constant state of being accelerated.

It is this loss of energy by the electron and the proton which would cause the their orbits to decay. Since they would each experience the same force, they would emit the same radiation. Because it is 2000x more massive the proton's orbit would decay much slower.

blue_zoo22 had a great answer, but not the one I was looking for.

2007-12-21 16:55:25 · update #2

10 answers

The electron goes first.
Next comes the proton after 2000 longer time.
The neutron remains in orbit forever.

They are orbiting around the hole, right?
In absence of other forces than gravity they will orbit forever. The charged particles in orbit, however radiate at same rates. But electron had 2000 less kinetic energy and will lose all its erergy to radiation first.

2007-12-21 10:04:30 · answer #1 · answered by Alexander 6 · 5 2

Well, have you heard of the Swartzschild radius for finding the radius of a black hole here is the equation:

r = (2GM)/c^2
where G = 6.6725E-11 N*m*m/kg*kg or m^3/s^2*kg
c= 299792458 m/s speed of light
and M= mass of the black hole

now you have the general acceleration equation for large bodies:

a = (GM)/r^2

now substitute the r for 2GM/c^2 and you get

a = 1/(4GMc^4)

thus the velocity at which they fall depends exclusively on the mass of the black hole as should be since it is easily observed here on earth. The mass of the particles are irrelevant in any instance.

2007-12-21 11:52:01 · answer #2 · answered by (Ω)Carlos S 2 · 1 1

The neutron would fall in first. The massive magnetic field surrounding the black hole would cause the charged particles (electron and proton) to experience a force as they moved through through it, causing them to spiral into the black hole.

2007-12-21 10:07:17 · answer #3 · answered by Anonymous · 2 1

They'd all fall in simultaneously. The gravitational force of the black hole would overwhelm and cancel out any physical effects the neutron, proton and electron may have on their environment which could slow their descent into it.

2007-12-21 09:50:39 · answer #4 · answered by Anonymous · 1 2

do no longer hear to Pissed Limey - tidal forces are forces that pull unequally on diverse factors of a physique. that's what the moon does to the earth to reason the tides (its gravity pulls the portion of the earth closest to it, inflicting the water to pass). the belief of tidal forces in a black hollow is that the gravitational pull of the hollow is so extreme that if, say, you have been getting into ft first the pull at your ft could be greater advantageous than at your waist so it may pull your ft speedier than your waist, to that lead to fact ripping you aside. in case you have been getting into head first your head could get pulled off. fairly, top? Btw, you are able to't purely get sucked right into a black hollow, you need to be heading in the direction of it with a velocity for it to do something besides keep you in perpetual orbit.

2016-11-04 05:53:53 · answer #5 · answered by ? 4 · 0 0

they would fall in at the same time except the electron would fall in like 0.0000000000000000001 of a second late or sooner i forget due to a very weak but still ther electromagnetic field that sorounds it

2007-12-21 11:03:28 · answer #6 · answered by nathan_french@sbcglobal.net 1 · 0 1

Neutron. THE other two when in motion create a force that resists their motion.

2007-12-21 09:51:02 · answer #7 · answered by donfletcheryh 7 · 4 1

If I drop 2 items from a tall tower at the same time/hight, they would hit the ground at the same time.

I am guessing the same basic principle would apply to dark holes.

All at the same time.

2007-12-21 09:55:53 · answer #8 · answered by robomoza777 2 · 1 3

I don't actually know but if it was based on mass and density it would be the electron wouldn't it?

2007-12-21 09:51:33 · answer #9 · answered by Billie V 3 · 1 1

the proton because it has more mass than the electron

2007-12-21 09:52:15 · answer #10 · answered by Anonymous · 3 3

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