1. (7 + sqrt 3) (7-sqrt 3)
2. sqrt 75a^2 divided by sqrt 5
2007-12-21 09:12:36 · 5 answers · asked by God Bless America!~ 4 in Science & Mathematics ➔ Mathematics
49-7sqrt3-7sqrt3- 3= 46
sqrt 75a^2 / sqrt 5
sqrt 25 *sqrt 3 a^2 /sqrt 5
5a *sqrt3 / sqrt 5
2007-12-21 09:56:57 · answer #1 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
(7 + â3 )(7 -- â3) = (7)^2 -- (â3)^2 = 49 -- 3 = 46
â(75a^2) / â5 = â(5^2*3*a^2) / â5 = 5aâ(3) /â5 = aâ5*3 = aâ15
2007-12-21 17:27:27 · answer #2 · answered by sv 7 · 0⤊ 0⤋
Difference of 2 squares: a^2 - b^2 = (a + b)(a - b)
So in your case a = 7 and b = sqrt 3
7^2 - sqrt(3)^2 = 49 - 3 = 46
2. Assume 75^0.5 x^2 div 5^0.5?
75 ^0.5 = ( 5 x 5 x 3) ^0.5
So 75^0.5 div 5 ^0.5 = (3 x5)^0.5
Ans 15^0.5 x^2
2007-12-21 17:24:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1)
(7 + â3)(7 - â3)
=>49 - 3 = 46 (since (a+b)(a-b) = a^2 -b ^2)
2)
â75a^2 / â5
=>â(5a)^2*5 / â5
=>5aâ5 / â5 = 5a
2007-12-21 17:19:23 · answer #4 · answered by mohanrao d 7 · 0⤊ 0⤋
46
you multiply and add
1st by 1st + 1st by 2nd + 2nd by 1st + 2nd by 2nd
49 + the next 2 terms add to make zero - sqrt 3 times sqrt 3
49 - 3
=46
2007-12-21 17:16:31 · answer #5 · answered by rosie recipe 7 · 0⤊ 0⤋