math help please?

Question

a sqrt 8 -3 sqrt 2a^2

Answer 1

a sqrt 8-3 sqrt 2a^2

a sqrt 4 *sqrt 2- 3 sqrt 2 * a^2

2a sqrt 2-3a sqrt 2= -a sqrt 2

Answer 2

I guess you mean solving the equation

a sqrt( 8 ) -3 sqrt (2 a^2) = 0.

Your equation is equivalent to the following two:

Case 1) If a is greater or equal to 0: a sqrt( 8 ) -3 sqrt (2) a = 0.

and the solution is a=0.

Case 2) If a is less or equal to 0: a sqrt( 8 ) +3 sqrt (2) a = 0.

and the solution is again a=0.

So the only solution is a=0.

If you mean just simplifying, then　it's

- sqrt(2) a (if a is posivite)

5 sqrt(2) a (if a is negative)

Answer 3

a sqrt 8 -3 sqrt 2a^2
sqrt 8 = 2 sqrt 2
sqrt 2a^2 = a sqrt 2,plug this in the originl binomial
a * 2 sqrt 2 - 3a sqrt 2 =
2a sqrt 2 - 3a sqrt2 =
- a sqrt 2

Answer 4

factor things

8 factors to 2^3 but I'll write that as (2^2)*2 to help you see this:
sqrt(8) = sqrt((2^2)*2) = sqrt(2^2) * sqrt(2) = 2sqrt(2)
so that simplifies the first term to 2asqrt(2)

you should immediately see that the second term simplifies this way
-3sqrt(2a^2) = -3asqrt(2)

so all together we have
2asqrt(2) - 3asqrt(2)
we can factor to get
(2-3)asqrt(2) = -asqrt(2)
that's the final answer

Answer 5

a√8 - 3√(2a^2)

=>a √(2^2*2) - 3√2(a)^2

=>2a√2 - 3a√2

=>√2(2a - 3a) = -√2*(a)

Answer 6

=2a sqrt2 - 3a sqrt2 = -a sqrt2

Answer 7

asqrt[8]-3sqrt[2a^2]=
asqrt[4*2]-3sqrt[2*a^2]=
2asqrt[2]-3asqrt[2]=
-asqrt[2]

Answer 8

no idea....sorry
what type of math is this?