English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories
0 ⤊

The heat of reaction for the following reaction is -827.4 kJ: 2PbS(s) + 3O 2 (g) → 2PbO(s) + 2SO2 (g)?

What is the enthalpy change when 5.2 mol of lead(II) oxide reacts with excess sulfur dioxide

2007-12-21 07:11:55 · 1 answers · asked by amanda R 1 in Science & Mathematics ➔ Chemistry

1 answers

2PbO(s) + 2SO2(g) ===> 2PbS(s) + 3O2 +827.4 kJ

5.2molPbO x +827.4kJ/2molPbO = 4302 kJ

2007-12-21 07:46:02 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋

fedest.com, questions and answers