2007-12-21 06:47:28 · 3 answers · asked by Kevin J 1 in Science & Mathematics ➔ Mathematics
log(base 4) of [12^(x-4)]
= (x-4) log(base 4) of (12)
= (x-4) log(base 4) of (4*3)
= (x-4) log(base 4) of 4 + (x-4) log(base 4) of 3
= (x-4)(1) + x log(base 4) of 3 - 4log(base 4) of 3.
= x - 4 + x log(base 4) of (3) - 4log(base 4) of (3).
2007-12-21 07:13:56 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
log is log to base 4 in the following:-
log 12^(x - 4) = (x - 4) log 12
2007-12-21 17:53:10 · answer #2 · answered by Como 7 · 1⤊ 0⤋
let log[4] (12)^(x-4)
12 can be written as 4^(1.792)
so log[4] (12)^(x-4) = log[4] (4^1.792)^(x-4)
=>log[4](4)^(1.792x - 7.168)
=>(1.792x - 7.168)log[4](4) (since log(a)^b = b loga)
=>(1.792x - 7.168)
( since log of any number to the base of same number is 1)
2007-12-21 15:35:03 · answer #3 · answered by mohanrao d 7 · 1⤊ 0⤋