2007-12-21 04:01:41 · 8 answers · asked by malkana d 2 in Science & Mathematics ➔ Mathematics
To simplify the given rational expression, first factorise the numerator and denominator:
(6y^2 - 5y - 6) / (9y^2 - 4)
= (3y+2)(2y-3) / (3y-2)(3y+2)
Then cancel the common factor (3y+2)
= (2y-3) / (3y-2)
This the expression in simplest form.
2007-12-28 23:29:56 · answer #1 · answered by Valithor 4 · 0⤊ 0⤋
(6y^2 - 5y - 6)/(9y^2-4)
factor numerator: (3y + 2)(2y - 3)
factor denominator: (3y - 2)(3y + 2)
each has a (3y + 2), so they cancel, leaving:
(2y-3)/(3y-2)
2007-12-21 04:08:46 · answer #2 · answered by miggitymaggz 5 · 0⤊ 0⤋
( 6 y ² - 5y - 6 ) / ( 9 y ² - 4 )
( 3y + 2 )( 2y - 3 ) / ( 3y - 2 ) ( 3y + 2 )
( 2y - 3 ) / ( 3y - 2 )
2007-12-25 06:30:41 · answer #3 · answered by Como 7 · 2⤊ 0⤋
(6y^2 - 5y - 6)/(9y^2 - 4)
=[(3y+2)(2y-3)]/(3y-2)(3y+2)
=(2y-3)/(3y-2)
2007-12-21 04:40:28 · answer #4 · answered by Kenneth Koh 5 · 0⤊ 0⤋
(6y^2 - 5y - 6)/(9y^2 - 4) =
[(3y + 2)(2y - 3)]/[(3y + 2)(3y - 2)] = (2y - 3)/(3y - 2)
2007-12-21 04:05:28 · answer #5 · answered by Cathy 2 · 0⤊ 1⤋
(6y^2 - 5y - 6)
____________
(9y^2-4)
=>(3y+2)(2y-3)
______________
(3y+2)(3y-2)
=>(2y-3)
________
(3y-2)
2007-12-21 04:11:41 · answer #6 · answered by mohanrao d 7 · 0⤊ 0⤋
=[(2y-3)(3y+2)]/[(3y+2)(3y-2)]
=2y-3/3y-2
2007-12-21 04:15:25 · answer #7 · answered by Anonymous · 0⤊ 0⤋
2y-3
_____
3y-2
2007-12-21 04:08:42 · answer #8 · answered by james brown 4 · 0⤊ 0⤋