I NEED HELP WITH CHEMISTRY HOMEWORK ABOUT MOLES and STUFF PLEASE!!!?

Question

okay so......

I need to find:

1) the mass of 350.0 L of Nitrogen, N2 at STP

2) What is the mass of 43.231 moles of Cu

3) How many moles are in 3.56 x 10^32 of N2

4) How many moles are in 4.38 x 10^42 atoms of zinc

5) how many atoms are in 2.41 x 10^24 molecules of water (H2O)

6) how many moles are in 403 grams of SO4

THANK YOU

-Colorado Boy

Answer 1

1] it is known that 1 mole of any gas at STP occupies 22.4 liters and nitrogen gas weighs 28g per mole, so:

28g/mole x 350 l/22.4l/mole = 437.5g

2] simply multiply the number of moles by the weight per mole:

43.231 moles x 63.546g/mole = 2747.2g or 2.7472 Kg

3] I presume you mean how many moles are 3.56 x 10^32 molecules of N2: A mole is defined as 6.02 x 10^23 molecules so just divide 3.56 x 10^32 by 6.02 x 10^23 to get your answer

I think you can see how it works now, I don't have time to do all your homework!

Answer 2

1)

V(N2) = 350L = 350dm3
Mr(N2) = 2 * 14 = 28g

28g : 22,4dm3 = X : 350dm3
X = 28 * 350 / 22,4 = 437,5g N2

2)

Mr(Cu) = 63,5g

63,5g : 1mol = X : 43,231mol
X = 2745.17g of Cu

3)

1mol : 6*10^23 = X : 3,56*10^32
X = 1 * 3,56*10^32 / 6*10^23 = 5,93 * 10^8 moles of N2

4)

1mol : 6*10^23 = X : 4,38*10^42
X = 0,805*10^19 moles of Zn

5)

1 molecule : 3 atoms = 2,41*10^24 : X
X = 3 * 2,41*10^24 = 7,23*10^24 atoms

6)

m(SO4) = 403g
Mr(SO4) = 32 + 4*16 = 96g

1mol : 96g = X : 403g
X = 403 / 96 = 4,198moles of SO4

Answer 3

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Answer 4

(a million) g Cu in 20 g CuO 20 g CuO x (a million mole CuO/ 80 g/mole) x (a million mole Cu/ a million mole CuO) x ( sixty 4 g/mole / a million mole Cu) = sixteen g Cu (2) g CuO containing precisely 1g Cu a million g Cu x ( a million mole Cu / sixty 4 g/mole ) x ( a million mole CuO / 1mole Cu) x (80 g/mole / a million mole CuO) = a million.25 g CuO (3) g Cu2O containing a million g Cu a million g Cu x ( a million mole Cu / sixty 4 g/mole) x ( a million mole Cu2O / 2 moles Cu) x (one hundred and 40 4 g/mole / a million mole Cu2O) = a million.one hundred twenty five g Cu2O :)