I need help on this one math question please
A right triangle is drawn with one of the non-right angles labeled with a measure of B degrees. The side opposite of the angle labeled b degrees is 12 units. The side adjacent to that same angle is labeled 15units. Find the value of b to the nearest hundredth. Show all work.
2007-12-21 02:41:38 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use the tangent function. tan(B) = 12/15 = 4/5 = 0.8, so B = arctan(0.8), which you can evaluate on a calculator. Make sure you know whether your calculator returns results in radians or degrees.
2007-12-21 02:44:03 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
You are given the side opposite and the side adjacent to the angle B.
The tangent ratio connects opposite and adjacent, so
tan B = 12/15, so
tan B= 38.66 degrees.
You need to remember the three trigonometric ratios:
Sin = opposite /hypotenuse.
Cos = adjacent/hypotenuse, and
Tan = opposite /adjacent.
Don`t forget that you can only use these ratios in this way in right angled triangles.
Hope this helps, Twiggy.
2007-12-21 10:49:54 · answer #2 · answered by Twiggy 7 · 0⤊ 1⤋
well you have the opposite and adjacent -thats tangent
so it would be done as : 12/15
that gives you : 0.8
2007-12-21 10:45:05 · answer #3 · answered by sambo369 3 · 0⤊ 0⤋
b=19.2
you can use this formula: Tan(q) = Opposite / Adjacent
2007-12-21 11:03:43 · answer #4 · answered by Leilan 1 · 0⤊ 1⤋
Pythagorean theorem?
2007-12-21 10:44:35 · answer #5 · answered by weeesa2004 1 · 0⤊ 3⤋