2007-12-18 17:22:25 · 7 answers · asked by Cindy C 2 in Science & Mathematics ➔ Mathematics
k³ (k² - 1)
k³ (k - 1)(k + 1)
2007-12-18 20:54:51 · answer #1 · answered by Como 7 · 3⤊ 0⤋
k^5 - k^3 = k ³ (k² - 1) = k ³ (k +1)(k - 1)
2007-12-19 01:32:08 · answer #2 · answered by piano 7 · 0⤊ 0⤋
k^3(k^2 - 1)
k^3(k + 1)(k - 1)
2007-12-19 01:30:59 · answer #3 · answered by ghostbuster 4 · 0⤊ 0⤋
k^3(k^2-1)
k^3(k-1)(k+1)
2007-12-19 01:58:42 · answer #4 · answered by Rayan Ghazi Ahmed 4 · 0⤊ 0⤋
(k^5-k^3)=k^3(k^2-1)
(k+1)(k-1)(k^3)
2007-12-19 05:11:02 · answer #5 · answered by techno_cart 1 · 0⤊ 1⤋
Take k^3 out and have the expression be k^3(k^2-1)
I think.
Yeah, what the first person said.
2007-12-19 01:25:32 · answer #6 · answered by vendetta4hire 3 · 0⤊ 1⤋
k^3(k^2 - 1) = k^3(k-1)(k+1)
Best of luck!
2007-12-19 01:25:23 · answer #7 · answered by disposable_hero_too 6 · 2⤊ 1⤋