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Can you help me with this calculus problem?
Oil Depletion, Suppose the amount of oil pumped from one of the canyon wells in Whittier, California, decreases at the continuous rate of 10% per year. When will the well's output fall to one-fifth of its present level?

2007-12-18 16:15:19 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

oil = original * (0.9)^t

t is in years

What you want is to find t such that
(0.9)^t = 0.2

log (base 0.9) each side:

t = log (base 0.9) 0.2

2007-12-18 16:21:51 · answer #1 · answered by Computer Guy 7 · 0 0

Let x0 be the amount of oil pumped at year zero
Next year x1 = x0 - 0.1x0 = x0(0.9)
Next year x2 = x1 - 0.1x1 = x1(0.9) = 0.9(0.9)x0
.
.
.
xn = xn-1 - 0.1xn-1 = xn-1(0.9) = (0.9)^(n)x0
If xn = 0.2x0 = (0.9)^(n)x0, what is n, the number of years
The x0's cancel so
0.9^n = 0.2
ln[0.9^n] = ln[0.2]
n ln[0.9] = ln[0.2]
n = ln[0.2]/ln[0.9] where n is the number of years

2007-12-19 00:28:00 · answer #2 · answered by kellenraid 6 · 0 0

Maybe soem geniuses know.

2007-12-19 00:19:52 · answer #3 · answered by Anonymous · 0 2

0.1 + 0.09 + 0.009 + 0.0009 + ...
= 0.1 + 0.09*1/(1 -- 0.1)
= 0.1 + 0.1
= 0.2
Never it will reach one - fifth.

2007-12-19 00:35:33 · answer #4 · answered by sv 7 · 0 0

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