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y=-5x^2-8x+2

2007-12-18 16:05:53 · 2 answers · asked by shatterpulse 1 in Science & Mathematics Mathematics

2 answers

The maximum will be the vertex. This will lie on the line of symmetry, which is always x = -b/(2a).
In this case, b = -8 and a = -5, so the line of symmetry is
x = -(-8)/(2*-5)
x = -8/10
x = -4/5

Plug this into the equation and solve for y. This will be your maximum value.

I hope this helps!

2007-12-18 16:13:16 · answer #1 · answered by math guy 6 · 0 0

If the quadradic is ax^2+bx+c, the maximum occurs at 0=2ax+b or x=-b/2a.

2007-12-18 16:12:46 · answer #2 · answered by cattbarf 7 · 0 0

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