the derivative of -8x/((1+x^2)^2)?

Answer 1

-8((1+x^2)^2) - (-8x)(2(1+x^2)*2x) / (1+x^2)^4

Thanks Ted!

Answer 2

take the bottom and work out the squared to get
-8x/ 1+x^4
then you use the quotient rule to get
((1+x^4)*(-8) - (-8x)*(4x^3)) / (1+x^4)^2
distribute and combine like terms to get
(24x^4-8)/(1+x^6)

Answer 3

"aanickaa" meant of course that the original bottom is squared...thus [1 + x^2]^4