Do a code trace. Follow the value of i
i starts as 20.
After the loop finishes, i *= 5 means 'multiply i * 5 and put the result back in I, so after the first iteration, i is 20 * 5, or 100.
After the next iteration, it will be 100 * 5, or 500.
500 is still small enough (barely) to stay in the loop, so the next iteration causes i to be 2500, which is too large, and the loop quits.
2007-12-18 15:04:04
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answer #1
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answered by Anonymous
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Just walk through it:
1. i starts out at 20. The condition 20 <= 500 is true so the loop executes (#1). Then i is incremented to 20*5, which is 100.
2. Now, 100 <= 500 is true so the loop executes again (#2) and i is set to 100*5, which is 500.
3. 500 <=500 is true, so the loop executes a 3rd time, and i gets set to 500*5.
4. At the next iteration, the conditional i<=500 is now false, so control passes to the next statement after the loop.
2007-12-18 15:04:23
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answer #2
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answered by daa 7
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well, this loop starts at twenty and goes to 500. If you were incrementing by one then you would have 480 times through the loop.
Since you are incrementing by a multiple of 5, you will have the first iteration, i=20, the second i=100, the third, i=500.
After that i=2500 which is greater than 500 so the loop ends.
Hope that helps
2007-12-18 15:00:21
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answer #3
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answered by jjhavokk439 2
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The following will happen when this for loop happens, I will use loop code to be any code that is inside the brackets:
1. I = 20;
2. is I <= 500 (yes, it is 20)
3. since it is, execute loop code
4. I *= 5 (equivalent to I = I * 5), since I was 20, it is now 100
5. is I <= 500 (yes, it is 100)
6. since it is, execute loop code
7. I *= 5, since I was 100, it is now 500
8. is I <= 500 (yes, it is 500)
9. execute loop code
10. I *= 5, since it was 500, it is now 2500
11. is I <= 500 (no, it is 2500)
12. loop is done (loop code does NOT execute again).
So it executes 3 times
2007-12-18 15:01:19
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answer #4
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answered by johnnyloot 3
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