Factor the expression 11(x + y) - 19 t(x + y)
Factor the polynomial 7 a ^8 b^ 9 c^ 7 - 21 a^ 9 b^ 7 c ^8
Factor 17 x ^2 + 17 x y + 19 x + 19 y by grouping
2007-12-18 13:41:06 · 4 answers · asked by Abena 2 in Science & Mathematics ➔ Mathematics
Factor the expression 11(x + y) - 19 t(x + y)
-(x+y)(19t-11)
Factor the polynomial 7 a ^8 b^ 9 c^ 7 - 21 a^ 9 b^ 7 c ^8
7a^8b^7c^7(b^2-3ac)
Factor 17 x ^2 + 17 x y + 19 x + 19 y by grouping
(17x+19)(x+y)
2007-12-18 13:50:48 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1. The first one has a () as a common factor. Factor it out and get, (x+y)(11-19t)
2. 7a^8b^7c^7(b^2- 3ac)
3. 17x(x+y)+ 19(x+y)= (x+y)(17x+19)
2007-12-18 13:54:34 · answer #2 · answered by oldteacher 5 · 0⤊ 0⤋
in the first equation - it's almost done. just regroup.
(11-19)(x+y) = -8(x+y)
2. pulling out the smallest of each number and/or letter we get 7a^8b^7c^7(b^2-3ac)
3. rearranging the equation: 17x^2+19x+17xy+19y
pulling out any like terms: x(17x+19)+y(17x+19)
notice how I have the same things in the ( )'s
(x+y)(17x+19) which is (outside stuff)(inside stuff)
2007-12-18 13:52:50 · answer #3 · answered by Alyx 2 · 0⤊ 0⤋
11x +11y-19tx-19 ty
7a^8b^7c^7(b^2-3ac)
x(17x+19)+ y(17x+19)
2007-12-18 13:48:27 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋