Find the limit: lim x→1 (2- 5/(x-2)^2
2007-12-18 13:11:59 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-3
use substitution
2007-12-18 13:16:38 · answer #1 · answered by Greyhound_Guy 2 · 0⤊ 0⤋
You are missing one parenthesis, but if you mean the x = 2 is squared, then we have
(2 -5)/ (x-2)^2 and as x goes to 1 we have (2-5)/(-1)^2 or
3 over 1 i.e. the limit is approaching -3 as x goes to 1
2007-12-18 21:25:53 · answer #2 · answered by Bernie R 5 · 0⤊ 0⤋
-3
substitute 1 for x and it becomes 2 - 5/1 which is 2-5
that gives u -3
2007-12-18 21:16:55 · answer #3 · answered by jo 2 · 0⤊ 0⤋
there's nothing special here, no hole, no asymptote. when x = 1, 2 - 5/(x-2)² = -3.
2007-12-18 21:18:01 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
34.7
2007-12-18 21:14:21 · answer #5 · answered by MJ 2 · 0⤊ 0⤋