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1. the expresion sin2x / 2cosx (sine 2 theta over 2 cosine theta) is equivlent too
a:sinx
b:cosx
c:tanx
d.cotx

2. which of the followiwng is the range of cos2x
a: -1 ≤ y ≤ 1
b: -2 ≤ y ≤ 2
c: -90 ≤ x ≤ 90
d: 0 ≤x ≤360

2007-12-18 12:53:13 · 1 answers · asked by Kelly S 1 in Science & Mathematics Mathematics

1 answers

The answer to 2 is a. That would be the answer for the RANGE of cos (almost anything), including this case.

For 1, recall that sin 2x = 2sinx cosx. After canceling, you're left with sin/cos.

And that looks a lot like c. :)

2007-12-18 14:08:17 · answer #1 · answered by Curt Monash 7 · 0 0

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