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i know you factor by grouping but i got x^2(x-2)25(-x+2) can you go any further?

2007-12-18 12:40:36 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

You have:

x²(x-2) + 25(-x+2)

Change the signs and use the distributive property, then finish with a difference of squares factorization:

x²(x-2) - 25(x-2)
(x² - 25)(x - 2)
(x + 5)(x - 5)(x - 2)

And we are done.

2007-12-18 12:45:03 · answer #1 · answered by Pascal 7 · 0 0

x^3 - 2x^2 - 25x + 50

x^2(x - 2) - 25(x - 2) {grouping}

(x^2 - 25)(x - 2)

(x + 5)(x - 5)(x - 2) {difference of two squares}

2007-12-18 20:46:36 · answer #2 · answered by kindricko 7 · 0 0

f(x) = x^3 - 2x^2 - 25x + 50

x^2(x - 2) - 25(x - 2)

=>(x - 2)(x^2 - 25)

now x^2 - 25 is in a^2 - b^2 form which equals (a+b)(a-b)

f(x) = (x-2)(x+5)(x-5)

2007-12-18 20:46:31 · answer #3 · answered by mohanrao d 7 · 0 0

(x^2 - 25)(x - 2) and (x^2 - 25) = (x+5)(x-5)

2007-12-18 20:44:50 · answer #4 · answered by S F 1 · 0 0

factor out -25

you get -25(x - 2)

then you get (x^2 - 25)(x-2)

which can be (x-5)(x+5)(x-2)

2007-12-18 20:45:20 · answer #5 · answered by Greyhound_Guy 2 · 0 0

your answer is correct (except you forgot the - before the 25). thats as far as you can go

2007-12-18 20:50:23 · answer #6 · answered by Emmy 2 · 0 0

not being mean but I have no idea. I think the first person was the best

2007-12-18 20:47:58 · answer #7 · answered by ? 3 · 0 0

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