9x^2-48x+64
2007-12-18 07:32:59 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
9x² - 48x + 64 = 0
The middle term is - 48x
Find the sum of the middle term
Multiply the first term 9 times the last term 64 equals 576 and factor.
Factors of 576
1 x 576
2 x 288
3 x 192
4 x 144
6 x 96
8 x 72
9 x 69
12 x 48
18 x 32
24 x 24. . .←. .Use these factors
- 24x and - 24x satisfy the sum of the middle term
Insert - 24x and - 4x into the equation
9x² - 48x + 64 = 0
9x² - 24x - 24x = 0
Group factor
(9x² - 24x) - (24x + 64) = 0
3x((3x - 8) - 8(3x - 8) = 0
(3x - 8)(3x - 8) = 0
- - - - - - - - -s-
2007-12-18 08:25:56 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
9x^2 -- 48x + 64
= 9x^2 -- 24x -- 24x + 64
= 3x(3x -- 8) -- 8(3x -- 8)
= (3x -- 8)(3x -- 8)
= (3x -- 8)^2
2007-12-18 07:37:01 · answer #2 · answered by sv 7 · 0⤊ 0⤋
this factors to (3x-8)(3x-8) or (3x-8)^2
your hint is that the first coefficient is a perfect square, and the final number is also a perfect square
2007-12-18 07:37:55 · answer #3 · answered by kuiperbelt2003 7 · 0⤊ 0⤋
(3x-8)(3x-8)
that's pretty simple; you probably got confused on the 3 part.
2007-12-18 07:38:26 · answer #4 · answered by the helper 2 · 0⤊ 0⤋
Sure - it is (3x-8)*(3x-8)
2007-12-18 07:36:31 · answer #5 · answered by nyphdinmd 7 · 0⤊ 0⤋
x=8/3,8/3
i.e.,(3x-8)*(3x-8)=0
2007-12-18 07:45:11 · answer #6 · answered by Shammi 1 · 0⤊ 0⤋