In total the jars contain 21 liter of wine. Each dwarf in turn gives all his wine to the others in equal shares. At the end of the process each dwarf has the same amount of wine as at the start. What was that?
2007-12-18 05:41:33 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm taking an educated guess. (I'll come back and figure this out), but I'm pretty sure that it is:
6, 5, 4, 3, 2, 1, 0
But, by the end of the evening, there will be no wine!
>>>>>>>>>>>>
Edit: 19 mins later.
Checked it out. You just keep going around in a circle with each dwarf having 6 liters of wine and passing out one liter of wine to each of his cohorts.
To Ralfcode.... Never seen this before, but I knew the last dwarf (dwarf g) had to have zero and the series had to descend from dwarf a to dwarf g.
2007-12-18 05:54:29 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 6⤊ 0⤋
21/7 = 3 liters
2007-12-18 05:46:24 · answer #2 · answered by Tim C 7 · 0⤊ 0⤋
a total of 21 liters
2007-12-18 05:53:12 · answer #3 · answered by HMS88 4 · 0⤊ 0⤋
3 liters
2007-12-18 05:44:32 · answer #4 · answered by Tina T 6 · 2⤊ 1⤋
Bad Santa nailed it - I just plugged his answer into a spreadsheet with the divisions plugged into it all. Good job!
BS, did you figure it out, or see this before?
2007-12-18 06:09:49 · answer #5 · answered by Ralfcoder 7 · 1⤊ 0⤋
They have 99 bottles of beer and they put them all on the wall
2007-12-18 05:52:59 · answer #6 · answered by skibm80 6 · 1⤊ 0⤋
WHOA. That was amazing. aha.
2007-12-18 05:44:53 · answer #7 · answered by Ariel 3 · 0⤊ 0⤋