8xy^4
2007-12-18 05:29:39
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answer #1
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answered by Anonymous
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Just so you know, one usually denotes the "to the power of" with the symbol ^.. so the question is:
(2y)(4xy^3) if I'm not mistaken...
In this case, you are comparing apples and apples (common factors) so you would simply multiply them as follows:
The constants get multiplied together: 2 * 4. That becomes 8.
Nothing happens to the x.
the ys get multiplied together, you get y^4.
So your answer is 8xy^4.
2007-12-18 05:31:49
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answer #2
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answered by Anonymous
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Assuming that second part is 4xy^3 (4xy to the 3rd power):
8xy^4
2007-12-18 05:30:34
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answer #3
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answered by Joe R 2
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8xy^4
2007-12-18 05:33:19
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answer #4
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answered by afronathan 3
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8xy^4
2007-12-18 05:31:19
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answer #5
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answered by jamiecd77 3
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1. 12 x y^2.
2. 48xy.
3. 64xy.
4. 32xy.
5. 24xy.
2007-12-18 06:00:21
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answer #6
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answered by Sasi Kumar 4
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8xy^4!
When multiplying variables, (such as x and y), you add them together...
ie. (x^2) (x^3) = x^5
2007-12-18 05:36:36
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answer #7
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answered by leesa246 2
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8xy^4 (2*4*x*y*y*y*y)
2007-12-18 05:30:35
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answer #8
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answered by michaell 6
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(2y)(4xy³) = 8xy^4
2007-12-18 06:05:48
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answer #9
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answered by Como 7
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(2y)(4xy3)
=24xy²
2007-12-18 07:00:02
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answer #10
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answered by Kenny2 3
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