√6 / √11 + 2
2007-12-18 05:25:31 · 4 answers · asked by . 1 in Science & Mathematics ➔ Mathematics
use the idea of the conjugate to get rid of sqrt ...
conjugate of sqrt(11)+2 = sqrt(11)-2
multiply both top and bottom by sqrt(11)-2
sqrt(6)*[sqrt(11)-2] / [sqrt(11)+2]*[sqrt(11)-2]
sqrt(6)(sqrt(11)-2sqrt(6) / [11-4]
[sqrt(66)-2*sqrt(6)] / 7
2007-12-18 05:33:10 · answer #1 · answered by grompfet 5 · 1⤊ 1⤋
â6 / â11 + 2,you multiply by â11 - 2/ â11 - 2
â6â11 - 2 / â11 + 2â11 - 2=
(â66 - 2â6) / ( 11 - 4 )=
(â66 - 2â6) / 7
2007-12-18 13:35:03 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You probably mean
â6 / [â11 + 2] = â6 [ â11 -2 ] / [11 - 4] = etc on your own
2007-12-18 13:31:06 · answer #3 · answered by lienad14 6 · 0⤊ 0⤋
â6 (â11 - 2) / (â11 + 2)(â11 - 2)
(â66 - 2â6) / (11 - 4)
(1/7) (â66 - 2â6)
(â6/7) (â11 - 2)
2007-12-18 14:11:03 · answer #4 · answered by Como 7 · 3⤊ 0⤋