Solve by completing the square x2 - 6x - 4 = 0.
-3 +
3 +
-3 + 2
3 + 2
2007-12-18 05:09:42 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x ² - 6x + 9) - 9 - 4 = 0
(x - 3) ² = 13
(x - 3) = ± √13
x = 3 ± √13
2007-12-18 06:13:30 · answer #1 · answered by Como 7 · 3⤊ 0⤋
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RE:
Solve by completing the square x2 - 6x - 4 = 0.?
Solve by completing the square x2 - 6x - 4 = 0.
-3 +
3 +
-3 + 2
3 + 2
2015-08-09 14:59:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
OK
x^2 - 6x -4 = 0
x^2 -6x -4 +13 = 13
x^2 -6x +9 = 13
(x-3)^2 = 13
So the answer is
3 +- sqrt 13.
Hope that helps.
2007-12-18 05:19:28 · answer #3 · answered by pyz01 7 · 0⤊ 0⤋
X 2 6x 4
2016-11-09 08:02:33 · answer #4 · answered by ? 4 · 0⤊ 0⤋
x2 - 6x - 4 = 0.
( x-3)^2-13 =0
(x-3)^2= 13
Either x= 3+√13
= 6.606
Or x= 3- √13
= -0.606
2007-12-18 05:14:47 · answer #5 · answered by MG 2 · 0⤊ 0⤋
x² - 6x - 4 = 0
x² - 6x = 4
x² - 6x + 9 = 4 + 9
( x - 3 ) ( x - 3 ) = 13
x - 3 = ±sqrt ( 13 )
x = 3 ± sqrt ( 13 )
2007-12-18 05:16:18 · answer #6 · answered by jgoulden 7 · 0⤊ 0⤋
x2-6x-4=0
x2-6x=4
x2-6x+(6/2)2=4+(6/2)2
x2-6x+(3)2=4+(3)2
(x-3)2=13
x-3=_/13
x=_/13 +3
i hope you can solve the rest for yourself
2007-12-18 05:26:32 · answer #7 · answered by monty 1 · 0⤊ 0⤋
(x-3)^2 = 13
x = 3+sqrt(13)
= 3-sqrt(13)
2007-12-18 05:16:04 · answer #8 · answered by Anonymous · 0⤊ 0⤋