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A container contains 2 mol of H2 and 1 mol of O2. Write down the probability that all the H2 is in the leftmost 2/3 of the container and all the O2 is in the rightmost 1/3.

I don't need a numerical answer for this, but I'm having trouble conceptualize a correct expression that will solve this problem.

Thank you!

2007-12-18 04:01:41 · 1 answers · asked by elan_longterm_invest 2 in Science & Mathematics Chemistry

1 answers

For each molecule of H2, there is a 2/3 probability that it will be in the leftmost part. So for 7 independently moving molecules, just for example, the probability will be (2/3)^7, and for 2NA independently moving molecules, it will be (2/3)^2NA, where NA is Avogadro's number.

For your oxygen molecules, the probability is (1/3)^NA

For both these things to happen at once, the probability is got by multiplying those two separate probabilities together.

So, as you can see, it's just not going to happen.

2007-12-18 11:35:37 · answer #1 · answered by Facts Matter 7 · 0 0

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