2007-12-18 03:18:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Reading this as:-
(1/5) x = 4y + 2
4y = (1/5) x - 2
y = (1/20) x - 1/2
OR
20y = x - 10
x - 20y - 10 = 0
Depends how standard form is defined in your part of the world.
2007-12-18 06:17:45 · answer #1 · answered by Como 7 · 3⤊ 0⤋
1/5x = 4y +2
=> Do the cross multiplication
=>1 = 5x (4y +2 )
=> 1 = 20xy + 10x
=> 10x + 20xy - 1 = 0 (That the right answer).
2007-12-18 11:27:01 · answer #2 · answered by its_me_farhan2005 2 · 0⤊ 0⤋
1/5x=4y+2
x = 20y + 10
x - 20y = 10
2007-12-18 11:21:24 · answer #3 · answered by ben e 7 · 0⤊ 0⤋
standard form is ax+by=c
so you just subtract 4y\
1/5x-4y=2
2007-12-18 11:24:17 · answer #4 · answered by James 6 · 0⤊ 0⤋
if your looking to "find y", this is it.....
1/5x-2=4y, then y=1/(4*5)x-2/4
So y=1/20x-1/2
If this isn't what you were looking for let me know
2007-12-18 11:25:45 · answer #5 · answered by MurfDogger 2 · 0⤊ 0⤋