Use the Quadratic Formula To Solve The Equation.?

Question

Use the Quadratic Formula To Solve The Equation


4x^2 + 7x - 10 = 0

a. -7/8 + √104/2
b. -8/7 + √418/8
c. -7/8 + √209/8
d. -7/4 + √209/4



-3x^2 + 5x - 5 = 0

a. 5/3 + i√35/3
b. 6/5 + i√35/3
c. 5/6 + i√35/6
d. 5/6 + √36/6

ok you two get 10 pts...tomorrow i will put a question on here and it will have your name in it and just make sure you put any old answer........ kendizz- will get the points on this question and then cin will get the points for this one on the other. thanks =D

cidyah*** will get points for this one on the other question.

Answer 1

Question 1
x = [- 7 ± √(49 + 160) ] / 8
x = [- 7 ± √(209) ] / 8
Option c is meant to read thus.

Question 2
x = [ - 5 ± √(25 - 60) ] / (- 6 )
x = [ - 5 ± √(- 35) ] / (- 6 )
x = [ 5 ± i √(35) ] / (6 )
Option c is meant to read thus.

Answer 2

are you kidding me? It would take less time to do the calculations yourself, than to type all this into yahoo questions. I just answered your other quadratic eqution question so go look at that answer and then do the rest yourself. I will do the second one though, since it has imaginary numbers.

[-5 +- sqrt(25 - 4(-3)(-5))] / (2*-3)
[-5 +- sqrt(-35)] / -6
5/6 +- isqrt(35) / 6

Answer 3

This equation is of form ax2+bx+c
a = 4 b = 7 c = -10
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-7 +/-sqrt(7^2-4(4)(-10)]/(2)(4)
discriminant is b^2-4ac =209
x=[-7 +sqrt(209)] / (2)(4)
x=[-7 -sqrt(209)] / (2)(4)
(C)
This equation is of form ax2+bx+c
a = -3 b = 5 c = -5
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-5 +/-sqrt(5^2-4(-3)(-5)]/(2)(-3)
discriminant is b^2-4ac =-35
(C)

Answer 4

for que1...answer is c.

for que 2...answer is c.