side A is 11'
side b is 12'
the base is 19'
and the hieght is6'
2007-12-18 02:01:36 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
use ar(triangle)=1/2*base*height
= 1/2*19*6
= 57
This is true when height is corresponding to that base.....
2007-12-18 02:04:05 · answer #1 · answered by Ayush J 2 · 0⤊ 0⤋
Area of triangle = (base x height) / 2
=> ( 19 x 6 )/2 = 57'
2007-12-18 02:04:54 · answer #2 · answered by Nai 4 · 0⤊ 0⤋
Area is 1/2bh so 19*6=114 1/2*114=57
2007-12-18 02:06:33 · answer #3 · answered by swimmer12_9 2 · 0⤊ 0⤋
Area = 1/2 X Base X Height. so
Area = 1/2 X 19ft X 6ft = 57sq ft
2007-12-18 02:06:11 · answer #4 · answered by DaveNCUSA 7 · 0⤊ 0⤋
area of triangle = run (base) X rise (height) divided by 2.
11' x 12' = 132' / 2 = 66'
19' x 6' = 114' / 2 = 57'
2007-12-18 02:44:40 · answer #5 · answered by kioskee2003 1 · 0⤊ 0⤋
6*19/2 = 57 ft^2
2007-12-18 02:05:57 · answer #6 · answered by ironduke8159 7 · 0⤊ 0⤋
[05]
The area of the triangle is
1/2*19*6 sft
=57 sft
2007-12-18 02:05:21 · answer #7 · answered by alpha 7 · 0⤊ 0⤋
1/2*b*h...that is all you need for the area
2007-12-18 02:09:17 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A squared plus B squared equals C squared
2007-12-18 02:03:35 · answer #9 · answered by sunshyn1919 5 · 0⤊ 2⤋
Ãrea do triângulo ABC = b.h/2
__
b = base
h = hieght
__
Ãrea do triângulo ABC = 19.6/2
Ãrea do triângulo ABC = 114/2
Ãrea do triângulo ABC = 57'
2007-12-18 02:07:33 · answer #10 · answered by Kíria 5 · 0⤊ 0⤋