The denominator is not equal to zero, simplify:
(a^4b^3)/(a^7b)
2007-12-18 01:54:42 · 8 answers · asked by speedndelko4u 1 in Science & Mathematics ➔ Mathematics
(a^4) ( b ³ )
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(a^7) ( b )
b ²
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a ³
2007-12-21 20:44:37 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Presuming you meant (a^4 x b^3)/(a^7 x b) you just need to subtract the indices on the bottom from those on the top.
i.e. (a^(4-7) x b^(3-1)) = (a^(-3) x b^2) = (b^2)/(a^3) since a power in the denominator (bottom) is the same as a negative power in the numerator (top)
so the answer is (b^2)/(a^3)
2007-12-18 10:03:21 · answer #2 · answered by cityboy516 2 · 0⤊ 0⤋
b^2 / a^3
2007-12-18 09:58:36 · answer #3 · answered by Dr D 7 · 0⤊ 0⤋
b^2/a^3
2007-12-18 09:58:47 · answer #4 · answered by Ashley M 2 · 0⤊ 0⤋
b^2/a^3
2007-12-18 09:58:35 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
Play the 'where are there more' game.
Where are there more a's? On the bottom. By how many? 3.
Answer has a^3 on the bottom.
Where are there more b's? On the top. By how many? 2.
Answer has b^2 on the top.
(b^2)/(a^3)
2007-12-18 10:01:31 · answer #6 · answered by JG 5 · 0⤊ 0⤋
(a^4b^3)/(a^7b)
=(a^4/a^7)*(b^3/b)
=1/(a^3)*b^2
=b^2/a^3
2007-12-18 09:58:20 · answer #7 · answered by Ayush J 2 · 0⤊ 0⤋
u = a (ab)^3/b(a^7)
u = 1/b * (b/a)^3
2007-12-18 09:59:34 · answer #8 · answered by Nur S 4 · 0⤊ 0⤋