solve the equation.
9x^2 + 36 = 0
a. -2,2
b. -4i, 4i
c. -2i, 2i
d. -1/2i, 1/2i
49x^2 + 36 = 0
a. -6/7i, 6/7i
b. -6/7, 6/7
c. -7/6i, 7/6i
d. -36/49i, 36/49i
2007-12-18 01:47:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[03]
9x^2+36=0
9x^2= -36
x^2= -36/9= -4
x=+-2i
Option c is the correct choice
49x^2+36=0
49x^2=-36
x^2= -36/49
x=+-6/7 i
option a is the correct choice
2007-12-18 01:56:58 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
In both cases, what you do to one side of the equal sign you must do to the other.
9x^2=-36
x^2=-4
x=+ or - 2 time the sqrt of -1, which is i
so it's c.
The second one is the same kind of problem
49x^2 = -36
7x^2 = -6
x = + or - 6/7 times the sqrt of -1, the imaginary i! so it, too, is c.
2007-12-18 09:54:47 · answer #2 · answered by Ken 7 · 0⤊ 0⤋
c and a
1. x^2=-4
x=-2i,2i
2. x^2=-36/49
x=-6/7i,6/7i
hope these are correct...
2007-12-18 09:56:55 · answer #3 · answered by geeno 2 · 0⤊ 0⤋
1. the answer is 2i so it should be C
2. A
2007-12-18 09:55:20 · answer #4 · answered by James 6 · 0⤊ 0⤋