In a dihybrid cross of heterozygotes, what proportion of the offspring will be phenotypically dominant for bot

Question

h traits?

A. 1/16
B. 3/16
C. 1/4
D. 9/16
E. 3/4

Answer 1

Your question cuts off, but if you're asking how many show the dominant form of both traits, and assuming the trait shows complete dominance (not co-dominance or incomplete dominance) the answer would be D.

Try working it out!

You can also do this mathmatically if you know that a cross for any one trait would have 3 dominant phenotypes to one recessive, then 3/4 x 3/4 = 9/16.

Answer 2

i desire to propose you make the effort to paintings by using a dihybrid circulate because it varieties the foundation of greater stepped forward genetic issues, yet listed decrease than are the bones of it/ The circulate is AaBb x AaBb. each and each parent produces 4 gametes AB Ab aB and ab, which you would be able to entice a Punnett sq. to get the sixteen genotypes. The phenotypic ratio is 9:3:3:a million dominant for the two:dominant for A recessive for B: recessive for A dominant for B: recessive for the two. So the respond on your question is 9/sixteen. The 9 class is composed of a million x AABB 2 x AaBB 2x AABb and four x AaBb