2007-12-11 02:23:48 · 3 answers · asked by joonsayin 1 in Science & Mathematics ➔ Engineering
The first response from mdernick is correct the faster way to do it would be to use the ratio of accelerations.
(120/32.2) X 15 lb
2007-12-11 15:51:54 · answer #1 · answered by Tim C 7 · 0⤊ 0⤋
The key is in the definition of 1 lb force which is different the one pound mass 1 lbf = 1 slug ft/sec^2
1 slug mass/32.2 ft/sec^2= .47 slugs
so Force = .47slugs * 120 ft/sec^2 = 55.95 lb
2007-12-11 11:06:59 · answer #2 · answered by rmtt2007 1 · 0⤊ 0⤋
This problem gets a bit tricky because oyu need to make sure you include g(sub)c in the equation:
F = ma/g(sub)c
m = 15 lbm
a = 120 ft/s^2
g(sub)c = 32.2 (whatever the unit is)
F = (15 * 120) / (32.2)
F = 55.9 lbf
2007-12-11 10:31:20 · answer #3 · answered by mdernick 2 · 1⤊ 0⤋