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any phase and neutral conductor?

2007-12-10 10:05:07 · 7 answers · asked by Paul 2 in Science & Mathematics Engineering

7 answers

In Europe, 400 Volts AC is the norm.

To Find the Line to Neutral Voltage in any three phase system, take the line to line Voltage and divide it by the square root of 3.

For 480 Volts -> 480 / 1.732 = 277 Volts

For 400 Volts -> 400 / 1.732 = 231 Volts

2007-12-10 11:19:50 · answer #1 · answered by harris_de 2 · 3 0

Assuming the electric service is from a 4-wire wye transformation:

400 V ÷ √3 = 231 V

I've heard some utilities outside the US use a 380 V system. 400 V is only 5% higher than 380 V. It is very likely that the customer is close to the substation where the voltage runs slightly higher than the nominal value.


The alternative answer below would be a remote possibility:

If the service came from a 4-wire delta transformation where one winding uses a center tap as the neutral/ground, there could be two answers.

200 V phase to neutral for two of the phases.
346 V from the "high phase" to neutral.

2007-12-10 11:30:04 · answer #2 · answered by Thomas C 6 · 1 1

The phase to phase voltage is equal to 400Vac and the voltage to neutral conductor is 400/1.732 = 230.9

2007-12-10 13:11:25 · answer #3 · answered by Anonymous · 0 0

the voltage is 480 generally, not 400, and it depends on how the transformers are wired.

The usual is delta, and with a 4-wire, center-tapped delta you must be careful of the High Leg. It must be identified with Orange tape and you must not use it for 120V single phase loads. That leg will give 208 between it and ground, while the others will give 120 volts, but be out of phase with each other.

2007-12-10 11:03:32 · answer #4 · answered by oklatom 7 · 0 3

Line voltage divided by 1.7321 that is phase voltage.
thats all.

2007-12-10 11:25:01 · answer #5 · answered by manoj260 2 · 1 1

80

2007-12-10 10:07:41 · answer #6 · answered by Xavier 4 · 0 3

400 v it does'nt add up like 220V single phase.

2007-12-10 10:11:33 · answer #7 · answered by Brad K 4 · 0 3

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