An FM radio station broadcasts on a frequency of 95.1 MHz. What is the length of a quarter-wave antenna design

Question

An FM radio station broadcasts on a frequency of 95.1 MHz. What is the length of a quarter-wave antenna designed to receive the signal from this station?
What is the energy associated with a photon of FM radio signal 95.1 MHz? Give answer in Joules.

Answer 1

wavelength (as stated above) = (2.99 * 10^8 m/s) / (95.1*10^6 Hz) = 3.14 m
1/4 of that is the length of the antenna.

Photons of that frequency have energy in Joules by the formula:
E = h * f
h is Plancks constant: 6.626 x 10^-34 J s
f is the frequency (in Hz)

E = 6.30 x 10^-26 Joules

As expected, these photons are not very energetic.

One more point: intensity, also called amplitude, of the carrier wave may be measured in 100s of thousands of kilowatts (for some commercial FM stations, effective radiated power) but that has nothing to do with the energy of each photon carrying the EM waves.

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Answer 2

Photons would not be associated with a frequency such as what you have given. The frequency is to low to be any where near that of light.
Full wave length for the frequency is 3.15 meters. I'll let you figure out the 1/4 wave length since this is probably your homework assignment anyway.
To give anything in Joules, some amount of energy level is needed, and you have not given anything that approaches anything about an energy level.

Answer 3

The formulation for era is T = a million/frequency. So, T = a million/(10^6 x 80 4.4) = a million.18 x 10^-8s. the clarification why I did 10^6 x 80 4.4 replaced into by way of fact it replaced into 80 4.4 Megahertz, that's 80 4,4 hundred,000 Hertz The formulation for wavelength is wavelength = velocity/frequency. So, 3.0 x 10^8 / (10^6 x 80 4.4) = .355m