if you bet 1 dollar on numbers 1 to 35 (35 on table) and leave 3 spots open (36, 0, 00) and you make one dollar every time 1 to 35 falls, you lose 35 dollars if 36, 0, and 00 fall. You can press your bet if you lose the first bet by going to 36 dollars on numbers 1 to 35. If you win, you win 36 dollars on that spin which makes the previous loss made back. If 36, 0, and 00 come twice in a row, you lose 1295 total. Is this a good way to bet against roulette, 35 out of 38 numbers by not losing twice in a row.
2007-12-10 04:58:46 · 12 answers · asked by Anonymous in Games & Recreation ➔ Gambling
If you had spent any time attempting this strategy on a roulette simulator or video game, you'd know it is a terrible strategy. This is why:
The odds of losing this bet are 3/38, which is about 1/12.67 So you're paying 35 to 1 for a bet that's going to lose at a rate of 12.67 to 1. You will lose twice in a row 1 out of every 160.4 spins. Since you have to win 1295 times in a row to break even, you will likely go broke in about 10 minutes using this strategy.
2007-12-10 14:13:39 · answer #1 · answered by Vegas Matt 7 · 1⤊ 0⤋
You are risking $35 to win $1 on the first bet. That is just plain foolish.
On the second bet, you are risking $1260 to turn a total profit of $1. That is moronic.
Actually, chances are good that you won't be able to make your second bet. Every casino has a maximum bet on each table, so you may not be able to make all of your bets.
The "strategy" Adam describes is called a Martingale. If you are very lucky, it might work in the short run. But over time, you will lose a LOT of money. If you hit a bad streak, you will lose your money very quickly.
The fact that this strategy has a name should indicate that Adam is not the first person to think of it. It has been around since the 1700s. If it worked, every casino in the world would be out of business.
It is similar to your "strategy" in that you will be betting a LOT of money to win a little bit of money.
In roulette, you are fighting a built-in house edge of 5.26%. No matter how you try to outsmart the odds, the math will eventually win out.
The only way to play roulette is to think of it as entertainment. Stick to a small, consistent betting amount. If you get lucky, take your money and run.
2007-12-10 06:21:00 · answer #2 · answered by John F 6 · 2⤊ 1⤋
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2014-06-04 05:31:53 · answer #5 · answered by Anonymous · 0⤊ 0⤋
got a better one for you
Put $5 on Black... 50/50 odds, you win..+5 you lose -5
not all tables have a 0 and 00, some only have one or the other. Find that table
Easier to play than laying down 35 separate chips every spin too.
2007-12-10 05:05:26 · answer #6 · answered by Daniel E 4 · 1⤊ 1⤋
Eh...try this: Bet one chip, whatever amount, on red (or black or even, etc...a 50-50 chance). If you lose bet 2 chips on the same thing. If you lose again bet 4, if you lose again bet 8, and keep doubling up. Eventually when you win, no matter when it is, you will be up. It can take some time, but if you have enough chips you will come out ahead.
I went to the casino last friday and brought $300 with me. I got all $25 chips and did this strategy. I came away with over $1100. If you have pacients and don't freak out when you are alot down, you will always come out ahead.
2007-12-10 05:33:03 · answer #7 · answered by Adam K 3 · 2⤊ 3⤋
I think statistically this a good bet . . . However, I played roulette this past weekend and "00" came up 3 in a row! I was $%@#!@#$#&
2007-12-10 05:06:22 · answer #8 · answered by Bob T 2 · 0⤊ 1⤋
Definitely not.
First off, even if u win that 36 dollars u lost another 1224 dollars by betting 36 dollars on 1-35.
The absolute best way to play roullette is to play red or black and vary ur bets.
2007-12-10 05:09:31 · answer #9 · answered by Anonymous · 1⤊ 1⤋
in the long run ( millions to spins) the house will make about 28% on every dollar. your system might let you play longer before you go broke.
2007-12-10 05:07:14 · answer #10 · answered by david_74056 3 · 0⤊ 1⤋