I'm looking the odds of playing 9 of the same numbers out of 37 possible and only hit one number in 55 spins. What are the odds?
2007-12-09 03:51:03 · 5 answers · asked by Paul T 1 in Games & Recreation ➔ Gambling
50/50
2007-12-09 04:01:47 · answer #1 · answered by Brad R 5 · 0⤊ 1⤋
1 in 257,013
This is essentially the same question you asked at
http://answers.yahoo.com/question/index;_ylt=AonEr3eE88NqphNJfkHyphn0xQt.;_ylv=3?qid=20071209142928AAyBwOF
except that you are using a 37 number wheel instead of a 38 number wheel.
Simply take the answer I gave to the other question and substitute 37 for 38 and 28 for 29 in the equation and you get
x = 1 / ((28 ^ 54 x 9 x 55) / (37 ^ 55))
2007-12-10 11:57:41 · answer #2 · answered by zman492 7 · 0⤊ 0⤋
actually your odds would be 9/37 since you don't have to hit a certain sequence of numbers. You would definitely hit out of 55 spins though. If you had to hit a sequence then your best bet would be to play the lottery
2007-12-09 14:26:10 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Doesn't a standard roulette wheel in the USA have 38 numbers (0 and 00)?
2007-12-09 17:03:50 · answer #4 · answered by H_A_V_0_C 5 · 0⤊ 1⤋
European Roulette. 495 to 2035 To take into account the occurrence of the event is much lower.
2007-12-11 23:27:15 · answer #5 · answered by Wylie Coyote 6 · 0⤊ 0⤋