Two men on the same side of a tall building notice the angel of elevation to top of the building to be 30 degrees and 60 degrees respectively. If the height of teh building is known to be h = 50 m, find the distance between the two men
2007-12-05 17:01:28 · 4 answers · asked by Cynical_Soul 1 in Science & Mathematics ➔ Engineering
assuming the angle between the wall and building is 90° then both men make a right triangle to top of the building so tangent of the angle made by the man 1 and top of the building times the height of the building is equal to distance the man is from the corner of the building and the tangent of the angle between the second man and the top of the building times the height of the building is equal to distance the second man is from the same corner of the building so the distance the second man is away from the corner minus the distance man one is away from the corner is equal to the distance the man are away from each other.
x = distance man 1 is from the corner
y = distance man 2 is from the corner
man 1: tan 30° = (x/50) simple algebra x = 50*tan 30° = 28.868
man 2: tan 60° = (y /50) simple algebra y = 50*tan 60° = 86.603
y - x = distance man are from each other
86.603 - 28.868 = 57.735 which is approximately 57.74 or 58 m
2007-12-05 17:26:00 · answer #1 · answered by K 3 · 0⤊ 0⤋
Apply the law of cosines
2007-12-06 01:11:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
my boyfriend said 58m
2007-12-06 01:11:17 · answer #3 · answered by lukewarm 2 · 0⤊ 0⤋
136.6 m?
2007-12-06 01:13:41 · answer #4 · answered by Dr. X to da Z 2 · 0⤊ 0⤋