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if i roll 3 dices with six sides, will the odds of getting 1,2,3 the same as 6,6,6.

2007-12-04 19:33:37 · 4 answers · asked by kara-siow 1 in Games & Recreation Board Games

4 answers

If order doesn't matter (i.e., 3-1-2 is the same as 1-2-3), then no. Consider the odds:

Odds of a getting a 6 on any die = 1/6
Odds of getting 6-6-6 = 1/6 * 1/6 * 1/6 = 1/216

Odds of getting a 1, 2, or 3 on the first die = 1/2
Odds of getting one of the other two numbers on the 2nd die = 1/3
Odds of getting the remaining number on the last die = 1/6
Odds of getting a 1, 2, and a 3 = 1/2 * 1/3 * 1/6 = 1/36

If order matters (that is, you have to roll a 1, then a 2, then a 3), the the odds would be the same - i.e., 1/216.

2007-12-06 17:58:44 · answer #1 · answered by JerH1 7 · 0 0

no the chances for all dice to be showing sixes is lower then getting 1,2,3.
To elaborate:
for 666 you need each and every dice to roll a 6. That's 1 out of 216 possible combinations.
for 123 your first die could be a 1 then the second be a 2 or 3 and the third takes what's left, so 2/216 here. same for rolling a 2 or a 3 with the first, so you end up with 6/216 or 1/36.

2007-12-04 22:30:12 · answer #2 · answered by Anonymous · 6 0

yes, odds are any combination of three numbers are equally likely.

2007-12-04 19:36:21 · answer #3 · answered by kktempo 3 · 0 2

yup its all the same.

2007-12-04 19:36:34 · answer #4 · answered by Adam S. 6 · 0 2

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