A weather balloon is filled with 11 L of helium on the ground wher the atomospheric pressure is 0.9 atm on that day.. If the balloon rises to a height of the atmosphere where the pressure is 0.3 atm, what will the new volume of the balloon be?
2007-12-04 17:57:48 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Assume no change in temperature, a reduction of pressure to one-third of initial should cause the volume to triple. So the answer would be 33 liters.
2007-12-04 18:05:48 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
The volume shouldn't change, only the density should.
2007-12-04 18:01:36 · answer #2 · answered by dantrc724 4 · 0⤊ 0⤋
P1V1=P2V2, so V2=P1V1/P2
P1=.9atm
V1=11L
P2=.3atm
V2=?
V2=.9(11)/.3 which is 33L when you calculate it out.
2007-12-04 18:13:36 · answer #3 · answered by ortegaphoto 1 · 0⤊ 0⤋