Calculate the molarity of the solution... 1.00 liter which contains 50.0 grams of NaOH (23+16+1=40g)?

Question

the answer is given 1.25 M but how do I get that?
thanks, studying for a Thursday test.

Answer 1

just remember that molarity is equal to 1 mol/1 liter

this is how you would set up your stoichiometry:
50.0 g NaOH/1Liter*1mol/40.0 g NaOh=1.25 mol/L or 1.25 M

Answer 2

(50 g) / (40 g/mol.) = 1.25 mol.
1.25 mol. solute per 1.00 L solvent = 1.25 M