9.0 grams of water in a 2.0 L pressure vessel is heated to 500 C. What is the pressure inside the container?

0 ⤊

(R=0.082 L atm/mol K, one mole of water has a mass of 1 grams)

2007-12-04 16:28:42 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics

PV = nRT
P = nRT/V
P = (9/18)(0.082)(500 + 273.12)/2
P ≈ 15.84896 atm. ≈ 16 atm.

2007-12-04 17:44:36 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

Thats 0.5mol water (18g/mol)

Use PV=nRT

One mole water=18g, NOT 1g.

2007-12-05 00:32:35 · answer #2 · answered by Ren Hoek 5 · 0⤊ 0⤋